Student in a hostel room use 100w electric lamp for 5 hours a day and a radiator of 500w for one hour a day .calculate the cost of running of these appliances for 30 days at rate of 30 paise per unit
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Answer:
Rs. 90
Explanation:
Electric Lamp,
Power = 100W
Time = 5 hours
Units per day = (Watt*Hours)/100
= [ (100*5)/100 ] kWh
= [ 500/100 ] kWh
= 5 kWh
= Units in a month = (5*30) kWh
= 150 kWh
Radiator,
Power = 500W
Time = 1 hour
Units per day = (Watt*Hours)/100
= [ (500*1)/100 ] kWh
= [ 500/100 ] kWh
= 5 kWh
= Units in a month = (5*30) kWh
= 150 kWh
= Total Units = (150+150) kWh
= 300 kWh
= Cost of 1 kWh = 30p
= Cost of 300 kWh = (300*30) paise
= 9000 paise
= Paise to Rupees = Rs. 1 = 100p
= 9000 paise = Rs. (9000/100)
= Rs. 90
Hope this helps.
kusum752000:
thanks
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