Student of a group have been divided into two groups in the ratio 6:11. If the first group has 870 student,how many student are there in all in the school
Answers
let as suppose a and b
ration of A and B = 6:11
A/B=6/11
870/B=6/11
870*11=6B
9570=6B
9570/6=B
1595=B
in Second Group Has 1595 Students
Student of a group have been divided into two groups in the ratio 6:11. If the first group has 870 student. There are 2465 students in all in the school.
Let the number of students divided in first group be 'x' and in the second group be 'y'.
It is stated that the ratio of the students in these 2 groups equal to 6:11. So,
x : y = 6 : 11
⇒ 6y = 11x
⇒y = (11/6)x ...(1)
It is given that the first group contains 870 students.
It means that, x = 870. So, putting the value of x = 870 in eqn.(1), we get,
y = (11/6) × 870 = 1595.
So, the second group contains 1595 students.
In total the school contains (x + y) number of students. [As the total number of students in the school were divided into 2 groups.]
So, total number of students = x + y = 870 + 1595 = 2465.
Thus, the school has 2465 students.