Question

Student of class 10 is given the task to plot the two equation on graph paper namely
PQ=2y-x=4 and RS =2x + y = 2 Based on task answer the question.
1. Co-ordinate where pq cut x-axis.
(a) (-4.0)
(b) (-3,0)
(c)(-2,0)
(d) (-1,0)
2. Co-ordinate where RS cut y-axis.
(a) (0, 1)
(b) (0, 2)
(c) (0, 3)
(d) (0,4)
3. The solution of both the equation.
(a) (0, 1)
(b) (1,0)
(c) (2,0)
(d) (0, 2)
4. Area formed by the two line and x-axis is.
(a) 3
(b) 4
(c) 4
(d)5
5. What is the nature of the solution of two equation.
(a) Unique
(b) Many
(c) No solution (d) None
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Answer 1

Step-by-step explanation:

1. (a) (-4, 0) because, coordinates of any point on x axis are always (x, 0) i.e. y = 0.
2. (b) (0, 2) because, coordinates of any point on y axis are always (0, y) i.e. x = 0.
3. the intersection of the two lines
4. using 1/2[x1(y3 - y2) + x2(y2 - y1) + x3(y1 - y3)] ( x1, y1), (x2, y2) & (x3 , y3) are vertices of triangle formed.
5. (a) unique.