Student while going to school in a school bus observed average speed of the bus is 20 km per hour on return along the same way the average speed is 30 kilometre per hour what is the average speed of the bus in entire journey.
Answers
Hey mate here's your answer if it helps plz plz mark me as brainliest.
As the student travels same path back & forth distance will be same. i.e. s1 = s2 = s.
As the student travels same path back & forth distance will be same. i.e. s1 = s2 = s.From home to school,
As the student travels same path back & forth distance will be same. i.e. s1 = s2 = s.From home to school,t1 = s1 / v1
As the student travels same path back & forth distance will be same. i.e. s1 = s2 = s.From home to school,t1 = s1 / v1t1 = s / 20
As the student travels same path back & forth distance will be same. i.e. s1 = s2 = s.From home to school,t1 = s1 / v1t1 = s / 20From school to home,
As the student travels same path back & forth distance will be same. i.e. s1 = s2 = s.From home to school,t1 = s1 / v1t1 = s / 20From school to home,t2 = s1 / v2
As the student travels same path back & forth distance will be same. i.e. s1 = s2 = s.From home to school,t1 = s1 / v1t1 = s / 20From school to home,t2 = s1 / v2t2 = s / 30
As the student travels same path back & forth distance will be same. i.e. s1 = s2 = s.From home to school,t1 = s1 / v1t1 = s / 20From school to home,t2 = s1 / v2t2 = s / 30Average speed of the bus will be calculated as -
As the student travels same path back & forth distance will be same. i.e. s1 = s2 = s.From home to school,t1 = s1 / v1t1 = s / 20From school to home,t2 = s1 / v2t2 = s / 30Average speed of the bus will be calculated as -v = (s1 + s2) / (t1 + t2)
As the student travels same path back & forth distance will be same. i.e. s1 = s2 = s.From home to school,t1 = s1 / v1t1 = s / 20From school to home,t2 = s1 / v2t2 = s / 30Average speed of the bus will be calculated as -v = (s1 + s2) / (t1 + t2)v = (s + s) / (s/20 + s/30)
As the student travels same path back & forth distance will be same. i.e. s1 = s2 = s.From home to school,t1 = s1 / v1t1 = s / 20From school to home,t2 = s1 / v2t2 = s / 30Average speed of the bus will be calculated as -v = (s1 + s2) / (t1 + t2)v = (s + s) / (s/20 + s/30)v = 2 / (20+30/20×30)
As the student travels same path back & forth distance will be same. i.e. s1 = s2 = s.From home to school,t1 = s1 / v1t1 = s / 20From school to home,t2 = s1 / v2t2 = s / 30Average speed of the bus will be calculated as -v = (s1 + s2) / (t1 + t2)v = (s + s) / (s/20 + s/30)v = 2 / (20+30/20×30)v = 2 × 600 / 50
As the student travels same path back & forth distance will be same. i.e. s1 = s2 = s.From home to school,t1 = s1 / v1t1 = s / 20From school to home,t2 = s1 / v2t2 = s / 30Average speed of the bus will be calculated as -v = (s1 + s2) / (t1 + t2)v = (s + s) / (s/20 + s/30)v = 2 / (20+30/20×30)v = 2 × 600 / 50v = 24 km/hr
As the student travels same path back & forth distance will be same. i.e. s1 = s2 = s.From home to school,t1 = s1 / v1t1 = s / 20From school to home,t2 = s1 / v2t2 = s / 30Average speed of the bus will be calculated as -v = (s1 + s2) / (t1 + t2)v = (s + s) / (s/20 + s/30)v = 2 / (20+30/20×30)v = 2 × 600 / 50v = 24 km/hrTherefore, average speed of the bus is 24 km/hr.
As the student travels same path back & forth distance will be same. i.e. s1 = s2 = s.From home to school,t1 = s1 / v1t1 = s / 20From school to home,t2 = s1 / v2t2 = s / 30Average speed of the bus will be calculated as -v = (s1 + s2) / (t1 + t2)v = (s + s) / (s/20 + s/30)v = 2 / (20+30/20×30)v = 2 × 600 / 50v = 24 km/hrTherefore, average speed of the bus is 24 km/hr.Thanks for asking.
Step-by-step explanation:
As the student travels same path back & forth distance will be same. i.e. s1 = s2 = s.
From home to school,
t1 = s1 / v1
t1 = s / 20
From school to home,
t2 = s1 / v2
t2 = s / 30
Average speed of the bus will be calculated as -
v = (s1 + s2) / (t1 + t2)
v = (s + s) / (s/20 + s/30)
v = 2 / (20+30/20×30)
v = 2 × 600 / 50
v = 24 km/hr
Therefore, average speed of the bus is 24 km/hr.
Thanks for asking.