Students A and B have probabilities of failing an exam of 1/2 and 1/5 respectively. The
probability of them both failing the examination is 1/10 Determine the probability that at
least one of the two students fail.
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Step-by-step explanation:
P(A)=1/2.
P(B)=1/5
P(AandB)=1/10 {probability of both failing}
probability that at least one fails is the probability that either one of two fails
P(AUB) = P(A) +P(B) -P(AandB)
= 1/2 + 1/5 - 1/10
= 0.5 +0.2 - 0.1
= 0.6 or 6/10
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