Students of a class are arranged in rows and columns. If there are 5 less rows, then there are 10 more number of columns formed and if there are 5 more rows, then number of columns formed are reduced by 5. The total number of students in the class are
Answers
Answer:
- There are 300 students in the class .
Step-by-step explanation:
Let, number of rows = x
and number of columns = y
then,
total number of students = x y
Now,
- According to the first condition when, there are 5 less rows then, there are 10 more columns formed , so
→ ( x - 5 ) ( y + 10 ) = x y
→ x y + 10 x - 5 y - 50 = x y
→ 10 x - 5 y = 50
→ 2 x - y = 10
→ y = 2 x - 10 ... eqn (1)
- According to the second condition when, there are 5 more rows then number of columns formed are reduced by 5 , so
→ ( x + 5 ) ( y - 5 ) = x y
→ x y - 5 x + 5 y - 25 = x y
→ - 5 x + 5 y = 25
→ y - x = 5
using eqn (1)
→ 2 x - 10 - x = 5
→ x = 15
putting value of x in eqn (1)
→ y = 2 x - 10
→ y = 2 ( 15 ) - 10
→ y = 20
so,
total number of students = x y
= ( 15 ) ( 20 )
= 300
therefore,
There are 300 students in the class .
Students of a class are arranged in rows and columns. If there are 5 less rows, then there are 10 more number of columns formed and if there are 5 more rows, then number of columns formed are reduced by 5. The total number of students in the class are.
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→ Let,
- → r = no. of rows
- → c = no. of columns
- → X = total students
→ r × c = X
→ (r-5) x (c+10) = X
→ (r+5) × (C-5) = X
- solve these equations simultaneous ,we get
→ 10r - 5c - 50=0
→ -5r + 5c - 25=0
→ 5r = 75
→ r =1 5
→ c = 20
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- Rows = 15
- Column = 20
- ★Total number of students in class
◆ Rows × column = 15 × 20 = 300
- Rows = 15
- Column = 20
- Total student in class = 300