Students of a class are made to stand in rows. If one student is extra in a row, there would be 2 rows less. If one student is less in a row there would be three rows more Find the number of students in class.
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Let the number of rows be x and number of students in a row be y.
Total students of the class
= Number of rows × Number of students in a row
= xy
condition(1)
Total number of students = (x − 1) (y + 3)
xy = (x − 1) (y + 3) = xy − y + 3x − 3
3x − y − 3 = 0
3x − y = 3 (1)
Condition (2)
Total number of students = (x + 2) (y − 3)
xy = xy + 2y − 3x − 6
3x − 2y = −6 (2)
solving equations we get
(3x − y) − (3x − 2y) = 3 − (−6)
− y + 2y = 3 + 6
y = 9
By using equation (1), we obtain
3x − 9 = 3
3x = 9 + 3 = 12
x = 4
Number of rows = x = 4
Number of students in a row = y = 9
Number of total students in a class = xy = 4 × 9 = 36
Let the number of rows be x and number of students in a row be y.
Total students of the class
= Number of rows × Number of students in a row
= xy
condition(1)
Total number of students = (x − 1) (y + 3)
xy = (x − 1) (y + 3) = xy − y + 3x − 3
3x − y − 3 = 0
3x − y = 3 (1)
Condition (2)
Total number of students = (x + 2) (y − 3)
xy = xy + 2y − 3x − 6
3x − 2y = −6 (2)
solving equations we get
(3x − y) − (3x − 2y) = 3 − (−6)
− y + 2y = 3 + 6
y = 9
By using equation (1), we obtain
3x − 9 = 3
3x = 9 + 3 = 12
x = 4
Number of rows = x = 4
Number of students in a row = y = 9
Number of total students in a class = xy = 4 × 9 = 36
Anonymous:
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Answered by
2
Answer:
60
Step-by-step explanation:
Let number of rows is x and number of students is y in a row.
Then total number of students = xy
A/C to question,
(x - 2)(y + 1) = xy
⇒xy + x - 2y - 2 = xy
⇒x - 2y = 2 -------(1)
Again, (x + 3)(y - 1) = xy
⇒xy - x + 3y - 3= xy
⇒ -x + 3y = 3 -------(1)
Solve equations (1) and (2),
y = 5 and put it equation (1)
x = 12
Hence, total number of students = xy = 12 × 5 = 60
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