Students of a class wrapped some gifts in the shape of rhombus to gift some needy people in Kerala.If the diagonals of rhombus are 24 cm and 10 cm ,what will be the length of its side?
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let ABCD be the rhombus where AC= 10cm
and BD = 24cm
let AC and BD intersect at O.
Now , diagonals of rhombus bisects eachother at right angles.
Thus we have
AO = (1/2)×AC = 10/2 = 5cm
BO = (1/2)×BD = 24/2 = 12cm
Since AOB is right angled triangle. So by Pythagoras theorem
we have
AB^2 = AO^2 + BO^2
AB^2 = 5^2 + 12^2
AB^2 = 25+144
AB^2 = 169
AB = square root of 169
AB = 13cm
Hence lenght of its side is 13cm .
hope it helps you
and BD = 24cm
let AC and BD intersect at O.
Now , diagonals of rhombus bisects eachother at right angles.
Thus we have
AO = (1/2)×AC = 10/2 = 5cm
BO = (1/2)×BD = 24/2 = 12cm
Since AOB is right angled triangle. So by Pythagoras theorem
we have
AB^2 = AO^2 + BO^2
AB^2 = 5^2 + 12^2
AB^2 = 25+144
AB^2 = 169
AB = square root of 169
AB = 13cm
Hence lenght of its side is 13cm .
hope it helps you
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