Students of a school were made to stand in rows for drill . If 3 students less were standing in each rows ,10 more rows were required and if 5students more were students in each rows then the number of rows was reduced by 10. Find the number of students participating in the drill
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Let the number of students in each row be x and the number of rows be y .
So , Number of students = xy
According to the question ,
(x-3)(y+10) = xy
=> xy+10x-3y-30 = xy
=> 10x-3y = 30 ..............(I)
Also ,
(x+5)(y-10) = xy
=> xy-10x+5y-50 = xy
=> -10x+5y = 50 ................(II)
Multiplying equation (I) by 1 and equation (II) by 1 , we get
10x-3y = 30
-10x+5y = 50
---------------------
2y = 80 { On Adding }
=> y = 40
So , From equation (I) ,
x = (3y + 30)/10
=> x = 15 .
So , Number of Students = xy = 15*40 = 600 ....
Hope It Helps .
Please Mark It As Brainliest ........
sujal2417:
thx a lot it helps
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