Students will fill in the missing fractions so that the sum of fractions on each side is
equal. Also, fractions must be written in their lowest forms.
Answers
1. 1/3+ x =7/12
x = 7/13 - 1/3
x =1/4
2. 2/3 + y =13/15
y = 13/15 - 2/3
y = 1/5
3. 3/10 + 1/5 = 1/12+z+1/6
5/10 = z + 3/12
z = 5/10 - 3/12
z = 1/4
Answer:
1) 1/4
2) 1/5
3) 1/4
Step-by-step explanation:
Concept= Fraction Addition
Given= Fractions and their sum
To find= The missing fraction values
Explanation=
We have been provided with the pictorial representation of the question where it says that we need to find the missing fraction in lowest form in an order such that the sum of the two is equal to the third.
We will suppose the missing fraction value x in the individual problems.
1) x+1/3=7/12
=> x= 7/12 - 1/3
=> x= (7-4)/12 (the lcm of 3 and 12 is 12)
=> x= 3/12 = 1/4
2) 2/3 + x= 13/15
=>x= 13/15 - 2/3
=> x= (13-10)/15 (lcm of 3 and 15 is 15)
=> x= 3/15= 1/5
3) 3/10 + 1/5 = 1/12 + x + 1/6
=> (3+2)/10 = (1+12x+2)/12 (Here the lcm of 10 and 5 is 10 and the lcm of
12 and 6 is 12)
=> 5/10 = (3+12x)/12
=> 1/2= (3+12x)12
=> 1=(3+12x)/6
=> 6= 3+12x
=> 6-3=12x
=> 3=12x
=> x= 3/12= 1/4
Therefore we have found all the missing fractions such that the sum of fractions of each side is equal.
#SPJ2