study the adjoining circuit and find the reading of ammeter
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Hey!!!
__________
We have
R1 = 4 ohm
R2 = 2 ohm
R3 = 2 ohm
V = 10V
Let R be the equivalent resistance of the circuit
Here R2 and R3 are in parallel
=> 1/Rp = 1/R2 + 1/R3
=> 1/Rp = 1/2 + 1/2
=> Rp = 1 ohm
Thus R = R1 + Rp
=> R = 1 + 4
=> R = 5 ohm
Again By Ohm's Law
=> V = I x R
Thus I = V/R
=> I = 10/5
=> I = 2A
Thus the ammeter reading will be 2A
____________
Note : Ammeter is connected in series not in parallel
Hope this helps ✌️
__________
We have
R1 = 4 ohm
R2 = 2 ohm
R3 = 2 ohm
V = 10V
Let R be the equivalent resistance of the circuit
Here R2 and R3 are in parallel
=> 1/Rp = 1/R2 + 1/R3
=> 1/Rp = 1/2 + 1/2
=> Rp = 1 ohm
Thus R = R1 + Rp
=> R = 1 + 4
=> R = 5 ohm
Again By Ohm's Law
=> V = I x R
Thus I = V/R
=> I = 10/5
=> I = 2A
Thus the ammeter reading will be 2A
____________
Note : Ammeter is connected in series not in parallel
Hope this helps ✌️
alamfarid3:
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