study the following circuit and find out
- current in 12 ohm resistor
-difference the readings of A1 and A2 is any
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answer : reading of both ammeters () are same. e.g., 0.25A
explanation : according to Kirchoff's law, let i is the current through the bigger loop as you see, both Ammeters are attached in bigger loop. so, current through both ammeters are same.
first of all, we have to find equivalent resistance.
Req = (24 × 24)/(24 + 24) + 12
Req = 24 × 24/48 + 12 = 24 ohms.
now, applying Ohm's law,
V = IR , I = V/R = 6/24 = 0.25A
hence, reading of both ammeters are same. e.g., 0.25A
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