Question

Study the following electric circuit. Find the readings of
(i) The ammeter.
(ii) The voltmeter.

Chapter - Electricity.​

Answer 1

Explanation:

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Answer 2

In the given circuit,

• The resistance of 4Ω and the bulb resistance of 2Ω are connected in series.

Now,

The equivalent resistance of the circuit will be

R = R₁ + R₂

R = 4 Ω + 2 Ω

R = 6 Ω

So,

• (i) The total current flowing in the circuit

$\boxed{(I) = \frac{Potential\ difference(V)}{Total resistance(R)}}$

($I$) = 3/6

($I$) = 0.5 A

In series combination the current which is flowing within each component of the identical and is equal to the total current flowing in the circuit.

Thus, 0.5 A current will flow through the ammeter, so the reading of the ammeter will be 0.5A

• (ii) Reading of Voltmeter = Potential Difference across 2Ω bulb

Therefore,

V = IR

   = 0.5 * 2

   = 1 V

[∴ As the current flowing through the bulb is 0.5 A]

Hence,

The readings of

• (i) The ammeter = 0.5 A
• (ii) The voltmeter = 1 V