Question

Study the following electric circuit in which two resistance of 10

ohm and 20 ohm connected in series and potential difference applied

is 3 volt, find (i) the equivalent resistance ii) the current flowing in

the circuit​

Answer 1

Answer:

i) 30 ohm

ii) 0.1 A

Explanation:

R1=10 ohm R2=20 ohm

(i)Req(series)= R1+R2

=30 ohm

From Ohm's law:-

V=IR

I=V/R

(ii)Current flowing in the circuit= 3 volt/ 30 ohm

=0.1 A

Answer 2

The equivalent resistance of the circuit is 30 Ω and the current flowing through the circuit is 0.1 amperes.

Given,

Two resistors of 10 Ω and 20 Ω are connected in parallel.

A potential difference of 3 volts is applied.

To Find,

The equivalent resistance of the circuit and the current flowing through it.

Solution,

The equivalent resistance of the circuit will be

R = R₁+R₂ { as the resistors are connected in series}

So,

R = 10+20

R = 30 Ω.

Now, using the ohm's law

V = RI

3 = 30*I

I = 3/10 = 1/10 = 0.1 amperes.

Hence, the equivalent resistance of the circuit is 30 Ω and the current flowing through the circuit is 0.1 amperes.

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