Question

Study the following picture.
1) What is the genotype for a pea plant heterozygous for round seeds (R), and homozygous recessive for green seeds (y)?
a) Ry b) RRyy c) RrYy d) Rryy

2)If round seed (RR) was dominant over wrinkled seed (rr) in a monohybrid cross, and yellow pod (YY) was dominant over brown pod (yy), what should be the starting genotype of parents in a dihybrid cross?
a) RRrr and YYyy b) RRYY and rryy c) RRyy and YYrr d) RrYy and RrYy

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Answer 1

Answer:

Explanation:

a] OPTION D Rryy

b] OPTION B RRYY and rryy

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Answer 2

Answer:

1. Genotype of a plant pea heterozygous for round seeds and homozygous recessive for green seeds is (d) Rryy.
2. Starting genotype of parents in a dihybrid cross would be (d) RrYy and RrYy

Explanation:

• Homozygous genotype is the genotype in which both alleles are of same expression. Example, RR,(round seed) rr(wrinkled seed), YY(yellow), yy(green).
• Heterozygous genotype is the genotype in which both alleles of same trait show different expression. Example, Rr, Yy.
• Dominance : Round seed (R) > wrinkled seed(r) and yellow seed(Y) > green seed(y).

1. The question tells about heterozygous condition of round seeds, so the genotype will be Rr and about homozygous condition of green seeds whose genotype would be yy. Combining both traits we get Rryy.
2. In a dihybrid cross, the parents taken are heterozygous for two traits.  Also the cross is developed by self cross between F1 generation which would be RrYy. Therefore, the genotype of parents would be RrYy and RrYy.

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