Question

Study the given aquatic food chain.
Answer the questions that follow.
Fish-eating
birds
(DDT S ppm)
Watge fish
ODI 2 ppm)
Veure
Small fish
DDT 05 ppmy
Zooplankton
(DON 004 ppm)
31727
Water
(DDT 0.003 ppb)​

Answer 1

Answer:

DDT is not soluble in water, so it will be least in water (0.003 ppm). It is seen that the level of DDT increases as the food chain progresses. It means, the primary consumers (zooplankton) will have more DDT concentration than the producers, the secondary consumers (small fish) will have more than primary consumers and so on. The highest concentrations will be seen in the top carnivore (fish eating bird). This is because the consumers at the successive trophic level consume more than the previous level to fulfil the energy requirements. Due to this, DDT keeps on accumulating in the successive trophic levels in higher concentrations. This process is called the biomagnification.

Hence, the correct answer is 'Water-0.003ppm, zooplankton- 0.04ppm, small fish-0.5ppm, large fish-2ppm, fish eating birds-25ppm'

Answer 2

Explanation:

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