Question

study the sequence 3, 8, 13, 18, what is the 20th term of the sequence
A. 2
B. 50
C. 9
D. 5
E. 98
F. 3​

Answer 1

Answer:

Here, a = 3 , t2 = 8, t3 = 13

d = t2 - t1 = 8 - 3 = 5

d = t3 - t2 = 13 - 8 = 5

:. d = 5

Formula - tn = a + (n-1)d

t20 = 3 + 19(5)

t20 = 3 + 95

:. t20 = 98.

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Answer 2

20th term of the sequence 3, 8, 13, 18 is 98

Given :

The sequence 3, 8, 13, 18

To find :

20th term of the sequence is

A. 2

B. 50

C. 9

D. 5

E. 98

F. 3

Concept :

If in an arithmetic progression

First term = a

Common difference = d

Then nth term of the AP

= a + ( n - 1 )d

Solution :

Step 1 of 3 :

Write down the given sequence

Here the given sequence is 3, 8, 13, 18

This is an arithmetic sequence

Step 2 of 3 :

Write down first term and common difference

First term = a = 3

Common Difference = d = 8 - 3 = 5

Step 3 of 3 :

Find 20th term of the sequence

20th term of the sequence

$\sf = a_{20}$

= a + ( 20 - 1 )d

= a + 19d

= 3 + ( 19 × 5 )

= 3 + 95

= 98

Hence the correct option is E. 98

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