Computer Science, asked by himansuranjan0pb1nl4, 1 year ago

Study the snippet given below and predict the output
int j,k,p=-1;
for(j=-2;j<=1;j++){
for(k=j;k<=0;k++)
k=Math.max(j*k,p);
System.out.print(k);
p=p+2;
}

Answers

Answered by dreamrob
30

Given:

int j,k,p=-1;

       for(j=-2;j<=1;j++)

       {

           for(k=j;k<=0;k++)

               k=Math.max(j*k,p);

           System.out.print(k);

           p=p+2;

       }

Output:

5241

Explanation:

p = -1

For j = -2

   k = j = -2

   k <= 0 → -2 <= 0 → True

       k = Max(j*k,p) = Max((-2)*(-2),-1) = Max(4,-1) = 4

       k++ → k = 5

   k <= 0 → 5 <= 0 → False

 Print(k) → 5

 p = p+2 = -1 + 2 = 1

 j++ → j = -1

 j <= 1 → -1 <= 1 → True

For j = -1

   k = j = -1

   k <= 0 → -1 <= 0 → True

       k = Max(j*k,p) = Max((-1)*(-1),1) = Max(1,1) = 1

       k++ → k = 2

   k <= 0 → 2 <= 0 → False

 Print(k) 2

 p = p+2 = 1 + 2 = 3

 j++ → j = 0

 j <= 1 → 0 <= 1 → True

For j = 0

   k = j = 0

   k <= 0 → 0 <= 0 → True

       k = Max(j*k,p) = Max((-1)*(0),3) = Max(0,3) = 3

       k++ → k = 4

   k <= 0 → 4 <= 0 → False

 Print(k) → 4

 p = p+2 = 3 + 2 = 5

 j++ → j = 1

 j <= 1 → 1 <= 1 → True

For j = 1

   k = j = 1

       k <= 0 → 1 <= 0 → False

 Print(k) → 1

 j++ → j = 2

 j <= 1 → 2 <= 1 → False

So, final output is 5241

Answered by bishnoisujal99
3

Given:

int j,k,p=-1;

      for(j=-2;j<=1;j++)

      {

          for(k=j;k<=0;k++)

              k=Math.max(j*k,p);

          System.out.print(k);

          p=p+2;

      }

Output:

5241

Explanation:

p = -1

For j = -2

  k = j = -2

  k <= 0 → -2 <= 0 → True

      k = Max(j*k,p) = Max((-2)*(-2),-1) = Max(4,-1) = 4

      k++ → k = 5

  k <= 0 → 5 <= 0 → False

Print(k) → 5

p = p+2 = -1 + 2 = 1

j++ → j = -1

j <= 1 → -1 <= 1 → True

For j = -1

  k = j = -1

  k <= 0 → -1 <= 0 → True

      k = Max(j*k,p) = Max((-1)*(-1),1) = Max(1,1) = 1

      k++ → k = 2

  k <= 0 → 2 <= 0 → False

Print(k) → 2

p = p+2 = 1 + 2 = 3

j++ → j = 0

j <= 1 → 0 <= 1 → True

For j = 0

  k = j = 0

  k <= 0 → 0 <= 0 → True

      k = Max(j*k,p) = Max((-1)*(0),3) = Max(0,3) = 3

      k++ → k = 4

  k <= 0 → 4 <= 0 → False

Print(k) → 4

p = p+2 = 3 + 2 = 5

j++ → j = 1

j <= 1 → 1 <= 1 → True

For j = 1

  k = j = 1

      k <= 0 → 1 <= 0 → False

Print(k) → 1

j++ → j = 2

j <= 1 → 2 <= 1 → False

So, final output is 5241

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