Question

study the time graph below and find objects distance and displacement
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Answer 1

Answer:

Sorry, but I didn't understand your question

Answer 2

distance = area of { ( △ABE ) + ( □ BEFC ) +

(△CFD)

=》[ (1/2 × 2 × 15) + {(5-2) ×15} + { 1/2 ×

(6-5) × 15}] m

=》(15 + 45 +7.5) m

=》67.5m

displacement = Area of ABCD

= area of{ ( △ABE ) + ( □BEFC ) +

(△CFD) }

= 67.5 m

*please note= the displacement and the distance

are equal as the graph given

above can only be drawn for

object going in a straight line.