Question

Study the vt graph of an ascending passenger lift in the figure shown below .what is the acceleration of the lift during the first 2 seconds ?during 10 seconds .during last 2 seconds? calculate the displacement for first 10 seconds.

Answer 1

Answer:

acceleration of the object from

i) t = 0 to t = 2

a = 3m/s/s

ii) t = 2s to t = 10s

a = 0

iii) t = 10s  to t = 12s

a = -3 m/s/s

displacement of the object from t = 0 to t = 10s is 54 m

Explanation:

As we know that acceleration is rate of change in velocity

So we have

$a = \frac{dv}{dt}$

so here from v-t graph we will have slope of the graph is acceleration of the object

i) from t = 0 to t = 2

acceleration = $\frac{6 - 0}{2 - 0}$

$a = 3 m/s^2$

ii) from t = 2 to t = 10

acceleration = 0 (as slope is zero)

iii) from t = 10 to t = 12

acceleration = slope

$a = \frac{0 - 6}{12 - 10}$

$a = - 3 m/s^2$

Now for displacement of object we know

$\Delta x = \int vdt$ = Area under v - t curve

so we have

$\Delta x = \frac{1}{2}(2)6 + (10 - 2)6$

$\Delta x = 54 m$

#Learn

Topic : Kinematics

https://brainly.in/question/10952930