Study the work shown below and compare the results to the product of –2i(6 – 7i). (0 – 2i)(6 – 7i) = (0)(6) + (0)(–7i) + (–2i)(6) + (–2i)(–7i) = 0 + 0 –12i + 14i2 = –12i – 14 = –14 –12i The products are
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