Question

su
बारम्बारता
100
S26
वर्ग
कतरान
0-100
100-200
200-300
17
300-100
५००-Soo
SOO-600
900-800
800-900
960-1000
Y y
५​

Answer 1

Answer:

ANSWER

Here,given

a=1

d=4−1=3

and,s

n

=287

Now,

s

n

=

2

n

(2a+(n−1)d)

⇒287=

2

n

(2×1+(n−1)3)

⇒287=

2

n

(2+3n−3)

⇒574=n(3n−1)

⇒574=3n

2

−n

⇒3n

2

−n−574=0

onsolvingthequadraticequaton