Question

suatu fungsi huruf linear ditentukan dengan rumus f(x) = ax+b jika diketahui f(-2) = -8 dan f(5) = 15 maka tentukan
a.nilai a dan b
b. nilai dari f(2)​

Answer 1

f(2)=(23/7)(2)+(-10/7)

=46/7-10/7

=(46-10)/7

=36/7

Answer 2

Answer:

The values of a,b & f(2) are

$\frac{23}{7} , \frac{ - 10}{7} , \frac{36}{7}$

respectively

Step-by-step explanation:

Given,

$f(x) = ax + b$

also given f(-2)=-8 and f(5)=15

$= = > a( - 2) + b = - 8 \\ = = > 2a - b - 8 = 0$

from f(5)=15

$5a + b - 15 = 0$

comparing both the equations we get

$a = \frac{23}{7} \: and \: b = \frac{-10}{7}$

therefore

$f(x) = \frac{23}{7} x - \frac{10}{7} \\ = = > f(2) = \frac{46}{7} - \frac{10}{7} = \frac{36}{7}$

#SPJ3