Question

SUB-MATHEMATICS( word problems on HCF alu L
Q1. Find the smallest number which on adding 19 to it is exactly divisible by
28, 36 and 45.
on pemainder​

Answer 1

For this first of all we have to find the LCM of 28, 36 and 45

So,

28= 2×2×7

36= 2×2×3×3

45= 3×3×5

Therefore LCM = 2×2×7×3×3×5 = 4×21×15= 84×15= 1260

Now, 1260-19 = 1241

Therefore 1241 is the number in which when 19 is added it will become exactly divisible by 28,36 and 45.

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