sub this by horizontal method
2x-3y+4z from 4x-6y-2
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Given polynomial 2x−3y+4z and 4x−6y−2
As per question
4x − 6y − 2 − (2x−3y+4z)
= 4x − 6y − 2 − 2x + 3y − 4z
= 4x − 2x − 6y + 3y − 2 − 4z
= 2x − 3y − 4z - 2
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