Question

subba rao started work in 1995 at an annual salary of ₹5000and received an increment of ₹200 eacj year .in which did his income reach ₹7000???


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Answer 1

Answer:

In year 1995 the salary = 5000

In year 1995 the salary = 5000+200 = 5200

And the last salary = 7000

So from the arithmetic progression,

$l = a + (n - 1)d$

$7000 = 5000 + (n - 1) \times 200$

$2000 = (n - 1) \times 200 \\ (n - 1) = 10 \\ n = 11$

So on 11th year (2006) after 1995 he reached to salary of 7000.

Answer 2

Hope it may help

In 2006 His salary wil be ₹7000