Question

Subba Rao started work in 1995 at an annual salary of ₹5000 and received an increment of 200 each year. In which year did his income reach ₹7000?

Answer 1

Subba Rao started work in 1995 at an annual salary of ₹5000 and received an increment of 200 each year.

This question is based on arithmetic progression.

where, first term, a = annual salary of subba Rao in 1995 = 5000

common difference, d = each year increment = 200

last term, Tn = 7000

use formula, Tn = a + (n - 1)d

or, 7000 = 5000 + 200(n - 1)

or, 2000 = 200(n - 1)

or, n = 11

hence in 11th years, his salary becomes 7000.

so, first year ⇒ 1995

2nd year ⇒1995 + (2 - 1) = 1996

3rd year ⇒1995 + (3 - 1) = 1997

..........

...............

11th year ⇒1995 + (11 - 1) = 2005

hence, in 2005 Subba Rao salary has become 7000.