Math, asked by debasishkhatei3, 5 months ago

subba rao started work in 1995 at an annual salary of rs. 5000 and recived an increment of ₹200 each year. in which year did his income reach₹7000?​

Answers

Answered by madhu20050110
3

Step-by-step explanation:

It can be observed that the incomes that Subba Rao obtained in various years are in A.P. as every year, his salary is increased by Rs 200.

Therefore, the salaries of each year after 1995 are

5000,5200,5400,…

Here, a=5000

d=200

Let after n

th

year, his salary be Rs 7000.

Therefore, a

n

=a+(n−1)d

⇒7000=5000+(n−1)200

⇒200(n−1)=2000

⇒(n−1)=10

∴n=11

Therefore, in 11

th

year, his salary will be Rs 7000.

Answered by siddhartha7765
1

Answer:

11

Step-by-step explanation:

taking a=5000,d=200

an=a+n-1×d

7000=5000+(n-1)×200

7000-5000=n-1×200

2000=n-1×200

2000÷200=n-1

10=n-1

n=10+1

n=11

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