Math, asked by gudalgovindramtha, 1 month ago

subba rao started work in 2015 at annual salary of Rs.50000 and received an increment of Rs.2000 each year. in which year did his income reach Rs.70000​

Answers

Answered by praptipatel04102005
0

Answer:

The incomes that Subba Rao earned is in A.P., as every year his salary is increased by Rs 200. Therefore, the salaries of each year from 1995 5000, 5200, 5400, … Here, a = 5000 d = 200 Let after nth year, his salary be Rs 7000. Therefore, an = a + (n − 1) d 7000 = 5000 + (n − 1) 200 200(n − 1) = 2000 (n − 1) = 10 n = 11 Therefore, in 11th year, his salary will be Rs 7000.Read more on Sarthaks.com - https://www.sarthaks.com/2281/subba-rao-started-work-1995-at-an-annual-salary-of-5000-and-received-increment-200-each-year

Answered by sachins01
1

Answer:

2017 subba rao reached a 70000 salary

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