Subhash is 3 years older than his brother Suresh .6 years ago Subhash's age was four times the age of Suresh find their present ages
Answers
Answered by
110
let suresh's age be x
then subhash's age is x + 3
six years ago
suresh's age = x - 6
subhash's age = x - 3
therefore, x - 3 = 4 * (x - 6)
x - 3 = 4x - 24
-3x = - 21
x = 7
therefore suresh's age is 7 yrs
subhash's age is 10 yrs
then subhash's age is x + 3
six years ago
suresh's age = x - 6
subhash's age = x - 3
therefore, x - 3 = 4 * (x - 6)
x - 3 = 4x - 24
-3x = - 21
x = 7
therefore suresh's age is 7 yrs
subhash's age is 10 yrs
Answered by
29
Suresh age = x
Subash age = x+3
6 yrs ago subash age = 4x
x+3 = 4x-6
6+3 = 4x-x
9 = 3x
x = 9/3
x=3
Subash age = x+3
6 yrs ago subash age = 4x
x+3 = 4x-6
6+3 = 4x-x
9 = 3x
x = 9/3
x=3
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