Question

Subhash is three years older than his brother suresh six years ago subhash's age was four times the age of suresh find there present ages

Answer 1

Answer:

Step-by-step explanation:

Let age of Suresh be x yrs

Age of subhash= 3+x yrs

Six years ago:

Age of subhash = (3+x)-6

Age of suresh = x-6

Given

(3+x)-6 = 4(x-6)

X-3 = 4x - 24

-3+24= 4x-x

21= 3x

X= 7 yrs. ( age of Suresh)

X+3=10 yrs. ( Age of subhash)

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Answer 2

let the present age of Suresh be x.

then the present age of Subhash = x+3

6 years ago, age of Suresh = x-6

6 years ago, age of Subhash = x+3-6 = x-3

according to question,

$4(x - 6) = x - 3 \\ 4x - 24 = x - 3 \\ 4x - x = - 3 + 24 \\ 3x = 21 \\ x = 7$

then the present age of Suresh = 7years.

then the present age of Subhash = x+3 =7+3 =10years.

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