Question

Subject: Mathematics
Scenario : TRAVELLING
Two friends Raju and Sanju plan to go from Asansol
to Kolkata by car. They travelled by a car with a
uniform speed of 40 kmph and reached the
destination in x hours. Next day, Raju alone
travelled from Asansol to Kolkata on his new sports
bike with a uniform speed and reached the place
one hour earlier than their previous travel time.
The total time taken for travelling both the days is 9
hrs
Question:4) What was the speed of the
sports bike?
A)
60 Kmph
B)
50 kmph
C)
70 kmph
D)
80 kmph​

Answer 1

Answer:

80 kmph is the right answer

Answer 2

Complete Question :- Two friends Raju and Sanju plan to go from Asansol to Kolkata by car. They travelled by a car with a uniform speed of 40 kmph and reached the destination in x hours. Next day, Raju alone travelled from Asansol to Kolkata on his new sports bike with a uniform speed and reached the place one hour earlier than their previous travel time. The total time taken for travelling both the days is 9 hrs .

Question:1) What is the distance between Asansol and Kolkata .

A) 500 km

B) 400 km

C) 200 km

D) 120 kn

Question 2) What was the speed of the sports bike?

A) 60 Kmph

B) 50 kmph

C) 70 kmph

D) 80 kmph

Solution :-

Let us assume that,

• Distance from Asansol to Kolkata = D km .
• Speed of Raju on bike = y km/h .

case 1) :- By car

→ speed = 40 km/h

→ Time = x hours .

so,

→ Distance = speed * time

→ D = 40x ------------- Eqn.(1)

case 2) :- By Bike

→ speed = y km/h

→ Time = (x - 1) hours.

so,

→ Distance = speed * time

→ D = y(x - 1) ----------- Eqn.(2)

also, given that,

→ Time (1) + Time (2) = 9 hours.

→ x + (x - 1) = 9

→ 2x - 1 = 9

→ 2x = 9 + 1

→ 2x = 10

→ x = 5 hours.

putting value of x in Eqn.(1) , we get,

→ D = 40x = 40 * 5 = 200 km (Option C) (Ans 1.)

hence, putting value of x and D in Eqn.(2) we get,

→ D = y(x - 1)

→ 200 = y(5 - 1)

→ 200 = 4y

→ y = 50 km/h . (Option B) (Ans.2)

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