Question

SUBJECT: MATHS

CLASS : VIII DATE : 21-05-2020



I. Solve the following. 10M



1. Find the solution using distributivity.

{ 7/5 x (-3/10) } + { 7/6 x 9/10 }



2. Simplify 2/5 + 3/7 + (-6/5) + (13/7).



3. Write the additive inverse of the following. (i) 5/8 (ii) -9/7.





4. Find 2/5 x (-1/9) + 23/180 – 1/9 x 3/4.



5. Find the product of 2/5 and reciprocal of 25/4.









​

Answer 1

Answer:

1.(-21/50) + (63/60)

= -21+63/60

= 42/60

= 0.7

2.

Answer 2

$\huge\red{\mathfrak{Answer}}$

1)

$\frac{7}{5} \times \frac{ - 3}{10} + \frac{7}{6} \times \frac{9}{10} \\ \\ = > \frac{ - 21}{50} + \frac{21}{30} \\ \\ = > \frac{ - 63 + 105}{150} \\ \\ = > \frac{42}{150}$

2)

$\frac{2}{5} + \frac{3}{7} + \frac{ - 6}{5} + \frac{13}{7} \\ \\ = > \frac{2}{5} - \frac{6}{5} + \frac{13}{7} + \frac{3}{7} \\ \\ = > \frac{ - 4}{5} + \frac{16}{7} \\ \\ = > \frac{ - 28 +80 }{35} \\ \\ = > \frac{52}{35}$

3)

$\frac{5}{8} = \frac{ -5}{8} \\ \\ \frac{ - 9}{7} = \frac{9}{7}$

4)

$\frac{2}{5} \times \frac{ - 1}{9} + \frac{23}{180} - \frac{1}{9} \times \frac{3}{4} \\ \\ = > \frac{ - 2}{45} + \frac{23}{180} - \frac{1}{12} \\ \\ = > \frac{ - 8 + 23 - 15}{180} \\ \\ = > \frac{23 - 23}{180} \\ \\ = > \frac{0}{180}$

5)

$\frac{2}{5} \times \frac{4}{24} \\ \\ = > \frac{1}{15}$

#BeBrainly