●SUBJECT-MATHS.●TOPIC-FRACTIONS
Q-1 Convert the following in lowest term.
(i)15\35 (ii)18/24
Q-2 Add the following
(i)5/9 + 2/9 (ii)5/6 + 3/4
Q-3 Subtract following
(i)10/1 - 9/1 (ii)11/12 - 10/9
Q-4 What should be added to 14/5 to get 6\7
Q-5 A tin contains 12/6kg ghee. How much kg of ghee contains in such 28 tins
♡Please tell answers with explanation guys♡
Answers
Refer to the attachment
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Q1) Convert the following in the lowest term.
(i) 15/35
(ii) 18/24
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Given :
- 15/35
- 18/24
To :
- convert the following in the lowest term.
Solution :
- Here, we have to divide the numerator and denominator by the HCF of the denominator and numerator.
⇒ Let's convert them.
- HCF of 15 and 35 = 5
→ 15/35
→ 15 ÷ 5/35 ÷ 5
→ 3/7
- HCF of 18 and 24 = 6.
→ 18/24
→ 18 ÷ 6/24 ÷ 6
→ 3/4
Q2) Add the following.
(i) 5/9 + 2/9
(ii) 5/6 + 3/4
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Given :
- 5/9 + 2/9
- 5/6 + 3/4
To :
- add the following fractions
Solution :
⇒ Let's add them.
→ 5/9 + 2/9
→ 5 + 2/9
→ 7/9
→ 5/6 + 3/4
→ 5/6 + 3/4 [LCM of 6 and 4 = 12]
→ (5 × 2/6 × 2) + (3 × 3/4 × 3)
→ 10/12 + 9/12
→ 10 + 9/12
→ 19/12
Q3) Subtract the following.
(i) 10/1 - 9/1
(ii) 11/12 - 10/9
--------------
Given :
- 10/1 - 9/1
- 11/12 - 10/9
To :
- subtract the following fractions
Solution :
⇒ Let's subtract the fractions.
→ 10/1 - 9/1
→ 10 - 9/1
→ 1/1
→ 1
→ 11/12 - 10/9
→ (11 × 3/12 × 3) - (10 × 4/9 × 4)
→ 33/36 - 40/36
→ 33 - 40/36
→ -7/36
Q4) What should be added to 14/5 to get 6/7?
--------------
Given :
- 14/5 to get 6/7?
To find :
- what should be added to 14/5 to get 6/7.
Solution :
14/5 + x = 6/7
x = 6/7 - 14/5 [LCM of 7 and 5]
x = (6 × 5/7 × 5) - (14 × 7/5 × 7)
x = 30/35 - 98/35
x = 30 - 98/35
x = -68/35
Q5) A tin contains 12/6kg ghee. How many kgs of ghee contains in such 28 tins?
--------------
Given :
- Tin contains = 12/6 kg ghee
To find :
- many kgs of ghee contain in such 28 tins.
Solution :
⇒ Let's find many kgs of ghee contain in such 28 tins.
One tine = 12/6 kg
28 = 12/6 × 28
= 12/6 × 28/1
= 12 × 28/6 × 1
= 336/6
= 56 kgs