Question

SUBJECT - PHYSICS
1. A tiger can accelerate from rest of 16m/s
i. What will be the velocity attained by it in 10 sec.
ii. How for will it travel in this duration?
2. At the end of a race, a runner decelerate from a velocity of 9.0m/s at a rate of 2.0m/s.
a. How for does he travel in the next 5s?
b. What is his find velocity?
c. How much time will it take to finally stop?
3. An object starts liwar motion with a velocity u and under uniform acceleration a, it acquires a velocity in time
t. Draw velocity time groph. From this graph obtain the second equation of motion.
4. Prove any two equation of motion.
5. State the reason for the following.​

Answer 1

Answer:

Ans1. I- u=0,a 16m/s^2, t=10second,v=?.

using formula “V=U+AT”.

V=0+16×10

V=160m/s.

ans ii-u=0,t=10 sec, a=16m/s^2,s=?

using formula “S=UT+1/2AT^2”

S=0×10+1/2 16×10×10

S=1/2 ×160×10

S=160×5

S=800meter.

ANS 2. i— u=9m/s,a=2m/s, t=5second, s=?

S=UT+1/2AT^2.

S=9×5+1/2×2×5×5.

s= 45+25

s=70m.

ii—u=9m/s,a=2m/s^2, t=5second.

FORMULA V=U+AT.

V=9+2×5

V=19m/s.

iii—70 METER.