Subject: Physics
9334 ५
M.Marks :D
Q. When an object is placed at a distance of 60 cm from spherical diverging
mirror the magnification produced is 0.5. Where should be the object placed to
produce magnification of 1/3.
102 Marks)
Answers
Answered by
1
Answer:
u=−60cm
u
−v
=
2
1
⇒
−60
−v
=
2
1
⇒v=30cm
⇒
v
1
+
u
1
=
f
1
⇒
f
1
=
30
1
+
−60
1
⇒
f
1
=
60
2−1
=
60
1
⇒f=60cm
Now magnification=
3
1
u
−v
=
3
1
⇒v=
3
−u
∴
v
1
+
u
1
=
f
1
⇒
3
−u
1
+
u
1
=
f
1
⇒
u
−3
+
u
1
=
60
1
⇒
u
−2
=
60
1
⇒u=−120cm
∴ Object should be placed at 120cm.
Explanation:
u=−60cm
u
−v
=
2
1
⇒
−60
−v
=
2
1
⇒v=30cm
⇒
v
1
+
u
1
=
f
1
⇒
f
1
=
30
1
+
−60
1
⇒
f
1
=
60
2−1
=
60
1
⇒f=60cm
Now magnification=
3
1
u
−v
=
3
1
⇒v=
3
−u
∴
v
1
+
u
1
=
f
1
⇒
3
−u
1
+
u
1
=
f
1
⇒
u
−3
+
u
1
=
60
1
⇒
u
−2
=
60
1
⇒u=−120cm
∴ Object should be placed at 120cm.
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