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10.0 mL solution of 0.050 M AgNO, was titrated with 0.0250 M NaBr in the cell:
S.C.E || titration solution | Ag(s)
Find the cell voltage for 30.0 mL of titrant.
A) +0.093 V
B) -0.039 V
C) -0.093 V
b) +0.039 V
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Answer:
B) -0.039 V
Explanation:
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