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Physics SEC-1
Ques. 1 (SMCQ)
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A block of mass 12kg is placed on a frictionless table. A heavy string of 18m length and havin
mass 9kg is connected to the block and force of 120N is applied on the string, then the tensio
point Pis:
12 kg
r
A
40N
B
120N
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Answer:
The tension at any point on the rope is basically what force acts on the remaining part.
Due to force F, the whole system would move with an acceleration of a=
M+m
F
At the midpoint of the rope the tension should be equal to the value of the force which would be able to pull the left part of the rope and the block with acceleration a.
∴T=(M+
2
m
)
M+m
F
Explanation:
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