submittion of 19 odd numbers
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0
Answer:
n (n+1)/6= 19(19+1)/6
Answered by
1
Answer:
Step-by-step explanation:
Firstly..... It's not submittion, it's summation.
It's means summing up or adding all the given nos.
Here, the summation of 19 odd nos. is asked.
It means
1 +3+5+7+9+.............( upto 19th odd number)
We know that every even no. Is of the form 2n where n =1,2,3.....
Every odd number is even number +1 (think over it)
Therefore every odd number is of the form (2n +1)
19th odd no. =2n +1 where n =19
=2multiplied by 19, +1
=38+1=39
Now you know the last term of summation
Use AP formula Sn equals n/2[2a +(n-1)d]
n =19, a=1 ,d=2
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