Math, asked by shaikrizwana9985, 1 month ago

Subract 5x-4xy2+6y-3from7x-4xy+8y2-3y​

Answers

Answered by suryapal1974cbse
1

Subract 5x-4xy2+6y-3from7x-4xy+8y2-3y

ans

7x-4xy+8y2-3y-(5x-4xy2+6y-3)

7x-4xy+8y2-3y-5x+4xy2-6y+3

7x-5x+4xy2-4xy+8y2-3y-6y-3

2x+4xy2-4xy+8y2-9y-3

2x+4xy2-4xy+8y2-9y-3 ans

Answered by ariestheracer
1

(7x - 4xy + 8y2 - 3y) - (5x - 4xy2 + 6y - 3)

= (7x - 4xy + 16y - 3y) - (5x - 8xy + 6y - 3)

= 7x - 4xy + 13y - 5x + 8xy - 6y + 3

= 2x + 4xy + 7y + 3

I was not so sure for the question so here's another one with square in it.

(7x - 4xy + {8y}^{2} - 3y) - (5x - {4xy}^{2} + 6y - 3)

= 2x - 4xy + {8y}^{2} - 9y + {4xy}^{2} + 3

Hope this will work!

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