Math, asked by psai2005, 2 months ago

subreact the second expression from the first expression

Answers

Answered by Answerpannel99
0

Answer:

where is the expression ??

Answered by Anonymous
2

Step-by-step explanation:

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(i) 2a + b, a + b

(ii) -2b + 2c, b + 3c

(iii) 5a + b, -6b + 2a

(iv) a^3-1+a,\ 3a-2a^2a

3

−1+a, 3a−2a

2

(v) p + 2, 1

(vi) x + 27 + z, -x - y - 3z

(vii) 3a^2-8ab-2b^2,\ 3a^2-4ab+6b^23a

2

−8ab−2b

2

, 3a

2

−4ab+6b

2

(viii) 4pq-6p^2-2q^2,\ 9p^24pq−6p

2

−2q

2

, 9p

2

(ix)10abc,\ 2a^2+2abc-4b^210abc, 2a

2

+2abc−4b

2

(x) a^2+ab+c^2,\ a^2-d^2a

2

+ab+c

2

, a

2

−d

2

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