Question

subset of 1, 3, 5, 7, 9, 11​

Answer 1

Answer:

So, the number of all its subsets is 2 to the power of 6 = 64, including the empty subset and the subset consisting of all 6 elements.

If you'd like to constrain yourself by only "proper" subsets, their number is 2 to the power of 6 - 2 = 64 - 2 = 62.

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Answer 2

Answer:

Given U={1,3,5,7,9,11,13},A={0},B={2,4},C={1,9,5,13},

D={5,11,1},E={13,7,9,11,5,3,1},F={2,3,4,5}

Now we have to find the subsets of U

Consider A={0}

Since 0∈

/

U,A⊈U

Consider B={2,4}

Since 2,4∈

/

U,B⊈U

Consider C={1,9,5,13}

Since 1,9,5,13∈U,C⊂U

Consider D={5,11,1}

Since 5,11,1∈U,D⊂U

Consider E={13,7,9,11,5,3,1}

Since 13,7,9,11,5,3,1∈U,E⊆U

Consider F={2,3,4,5}

Since 2,3,4∈

/

U,F⊈U

Therefore C,D,E are subsets of U.