Question

substact the sum of x²-3xy-3/2y² and 2x²+xy-2y² from the sum of 2xy-x²/3-3y² and -x²/3-xy/2+5y²​

Answer 1

Answer:

• x^2-3xy-3/2y^2+2x^2+xy-2y^2

=3x^2-2xy-7/2y^2====>> 1

• 2xy-x^2/3-3y^2-x^2/3-xy/2+5y^2

=-2x^2/3+xy+2y^2===>>2

2) -(1)

-2x^2/3+xy+2y^2-(3x^2-2xy-7/2y^2)

=-2x^2/3+xy+2y^2-3x^2+2xy+7/2y^2

=-11x^2/3+3xy+11y^2/2

×(-)

we get

=11x^2/3-3xy-11y^2/2