Question

substance of mass 5 kg is moving in y direction,force F=kt^2 is acting in the direction of motion,where k=15s^-2. The distance travelled by substance in the first 2 second_,and speed after 2 sec is_? plz dont spam​ plz ...give correct answer​

Answer 1

Explanation:

Our interest is in finding the moment when the velocity along X-axis becomes zero. So noting the initial velocity along X-axis as u=6m/s

Acceleration along X-axis is Force along X-axis/mass=−3/5=−0.6m/s

2

Time taken in making the velocity along X-axis to zero is change in velocity/acceleration=

(−0.6)

(0−6)

=10second

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Answer 2

140

Explanation:

We know that the Newton's second law of motion is F=

Δt

Δp

or change in momentum

or the gain in momentum is Δp=FΔt=Area under the F-t graph

The net area till the end of t=10s is consists of a trapezium with parallel side as 10second and 8−4=4second

and the separation being 20N so area or momentum is

2

sum×separation

=

2

(10+4)second×20N

=140Newtonsecond