Substance X is a compound containing 632 mg of manganese and 368mg of oxygen. Substance X is shown below. Manganese has a relative atomic mass of 55 and oxygen has a relative atomic mass of 16. What is the value of y in the formula below?
The 'below' is shown in the screenshot attached.
MnO∨y
If you answer this properly, I will mark you as the brainliest and thank you.
Please, EXPLAIN YOUR ANSWERS.
Attachments:
Answers
Answered by
5
Answer:
Explanation: We divide each constituent mass thru by the ATOMIC mass of each element:
Moles of manganese
=
63
⋅
g
54.94
⋅
g
⋅
m
o
l
−
1
=
1.15
⋅
m
o
l
.
Moles of oxygen
=
37
⋅
g
15.99
⋅
g
⋅
m
o
l
−
1
=
2.31
⋅
m
o
l
.
We divide thru by the smallest molar quantity, that of the metal, to give an empirical formula of
M
n
O
2
.
Answered by
5
Answer:
The answer is 2
Explanation:
Educake says so
Similar questions