Substitute 3x-5y+1=0 and x-y+1=0.
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just take x on one side and express in its terms and just solve it
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x-y+1 = 0
x = y-1 ......(1)
3x-5y+1 = 0
Substituting value of x from equation (1)
3(y-1) -5y = -1
3y - 3 - 5y = -1
-2y = 2
y = -1
x = y-1
x = -1-1
x = -2
x = y-1 ......(1)
3x-5y+1 = 0
Substituting value of x from equation (1)
3(y-1) -5y = -1
3y - 3 - 5y = -1
-2y = 2
y = -1
x = y-1
x = -1-1
x = -2
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