substitute 5x-3y=1 and 2x+5y=19
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the ans is x=2 and y=3
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5x-3y=1
5x=3y+1
x =(3y+1)/5
Put the value of x in second equ.
2x+5y=19
2[(3y+1)/5] +5y= 19
(6y+2)/5 +5 y=19
TAKE LCM
(6y+2)+ 25y= 19 ×5
31y+2 = 95
31y=95-2
31y= 93
y = 93/31
y= 3
now put the value of y in the first equ. to findx
5x-3y=1
5x-3(3)=1
5x-9=1
5x=10
x= 10/5
x= 2
I HOPE THIS ANS WILL HELP YOU
5x=3y+1
x =(3y+1)/5
Put the value of x in second equ.
2x+5y=19
2[(3y+1)/5] +5y= 19
(6y+2)/5 +5 y=19
TAKE LCM
(6y+2)+ 25y= 19 ×5
31y+2 = 95
31y=95-2
31y= 93
y = 93/31
y= 3
now put the value of y in the first equ. to findx
5x-3y=1
5x-3(3)=1
5x-9=1
5x=10
x= 10/5
x= 2
I HOPE THIS ANS WILL HELP YOU
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