substitute
f1 + f2=114
f1+2f2=152
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Answer:
f1=114-f2 eq(3)
putting this value in 2 equation, we get
114 -f2+2f2=152
f2=152-114
f2= 38
putting this value in eq(3), we get
f1= 114-38
f1= 76
hence , f1= 76 and f2=38
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