Question

Substitute the different pairs of numbers to find the different values of the expression given.

3x+y

(x, y) (3, 5) (−2, 3) (3, 2) (−1,−2)

Value

Answer 1

Answer:

The values of the expression at the points (3,5), (-2,3), (3,2) and, (-1,-2) are 14, -3, 11 and, -5 respectively.

Step-by-step explanation:

To find the value of the expression, we should substitute the value of $x$ and $y$.

The given expression is

$3x+y$

For the ordered pair (3,5), $x=3\ \&\ \ y=5$. So the value of the expression is,

$3x+y=3\times 3+5=9+5=14$

For the ordered pair (-2,3), $x=-2\ \&\ \ y=3$. So the value of the expression is,

$3x+y=3\times (-2)+3=-6+3=-3$

For the ordered pair (3,2), $x=3\ \&\ \ y=2$. So the value of the expression is,

$3x+y=3\times 3+2=9+2=11$

For the ordered pair (-1,-2), $x=-1\ \&\ \ y=-2$. So the value of the expression is,

$3x+y=3\times (-1)+(-2)=-3-2=-5$  .

Answer 2

Answer:

Step-by-step explanation:

1. for (x,y)

x=x and y=y

therefore,3x+y=3x+y only so it has no solution

2. for (3,5)

x=3&y=5

therefore,3x+y=3(3)+5

=6+5

=11

3.for (-2,3)

x=-2&y=3

therefore,3(-2)+3

= -6+3

= -3

4.for (3,2)

x=3&y=2

therefore,3(3)+2

=9+2

=11

5.for (-1,-2)

x= -1& y= -2

therefore, 3 (-1)+(-2)

=-3-2

=3+2

=5