substitute the given value 4 (5y/6)-3y=4
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If 3x + 5y = 6, then, multiplying by 2, 6x + 10y = 12. (1) Similarly,
if 2x - 3y = 4, then, multiplying by 3, 6x - 9y = 12. (2) Subtract (2) from (1) to get
(6x + 10y) - (6x - 9y) = 12 - 12 = 0 => 19y = 0 => y = 0. Substitute this into (1) or (2) to
get 3x = 6 or 2x = 4, so x = 2. A quick check shows 3x + 5y = 3*2 + 5*0 = 6 - 0 = 6 and
2x - 3y = 2*2 - 3*0 = 4 - 0 = 4, as needed. So (x,y) = (2,0) and you should be able to
solve any pair if linear equations by using this technique. Good Luck!
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